a particle is projected with a speed of 24m/s.find the two angles of projection to give a range of 14m

Question

Vikas TU · Answer

Dear Student,

For angular projection, we have R = (u²sin2θ)/g.

To get R = 14 m with θ = 24 m/s, we have 14 = 576 sin2θ/9.8

sin2θ = 14 x 9.8/576.

2θ = sin^-1 (14 x 9.8/576) = 13.78 degrees.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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a particle is projected with a speed of 24m/s.find the two angles of projection to give a range of 14m

a particle is projected with a speed of 24m/s.find the two angles of projection to give a range of 14m

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a particle is projected with a speed of 24m/s.find the two angles of projection to give a range of 14m

a particle is projected with a speed of 24m/s.find the two angles of projection to give a range of 14m

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