Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        if image of the point (2,1) with respect to a line mirror be (5,2), find the equation of the miror..... `
7 years ago

parth pankaj tiwary
18 Points
```										Let point (2,1) be A and (5,2) be B......... First find the equation of AB..... which i hope u can easily find.
After that the slope of the so called mirror will be -3  as mirror is always perpendicular to the image.........
After that find the midpoint of AB..........For sure this point wil lie on the mirror........Now u got slope and a point.....
its easy to find the equation now....... the answer will be 6x+2y-24=0
```
7 years ago
Nehal Wani
21 Points
```										Mid Point Of (2,1) and (5,2) is (7/2,3/2)
Slope of line joining (2,1) and (5,2) : 1/3
Slope of mirror line : -3
Equation of mirror line: [y-3/2]/[x-7/2]=-3
(2y-3)/(2x-7)=-3
2y-3=21-6x
2y+6x-24=0
y+3x-8=0
```
7 years ago
Sneha vyas
21 Points
```										First we will find the midpoint of (5,2) and (1,2),(2+5/2 , 2+1/2)i.e ( 7/2 , 3/2 )Now...we will find the slope of line formed by points (5,2) and (1,2)2-1/5-2= So slope is 1/3We will find slope of line perpendicular to this line with thw slope 1/3....So the slope of 2 perpendicular lines has a product of -1,Hence the slope of the line is  m×1/3=-1 => m=-3NOW,find eq. Of line passing through point (5,2) and having a slope of -3(y-3/2)/(x-7/2) =-32y-3/2x-7=-32y+6x=24y=-3x+12is the answerI hope u get it ALL THE BEST!
```
2 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details