MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
deepikA thotlavalluri Grade: 11
        

A square is inscribed in the circle x2 +y2 -10x-6y+30=0.One side of the square is parallel to the line y=x+3.Find the vertices of the square.

7 years ago

Answers : (1)

Nehal Wani
21 Points
										radius of circle = 2 = half of diagonal of square


therefore perpendicular distance of center of circle(5,3) from side of square=v2

equation of one side of square : y=x+k

by distance formula,

|5+k-3|/v2=v2

k=0,-4

the two side of square are: y=x and y=x-4

solving the lines with the equation of circle, we get:

vertices: (3,3),(5,5),(5,1),(7,3)
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 3,180 off
USE CODE: CART20
Get extra Rs. 297 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details