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deepikA thotlavalluri Grade: 11
        

The symmetric form of the equation of the line of intersection of the planes x+y-z = 1 and 2x-3y+z=2 is

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear deepika


planes x+y-z = 1 and 2x-3y+z=2


 


let the direction ratio of the line are a,b,c


so a+b-c =0   and 2a-3b+c =0


so from these two equation


 a/2  = b/3 =c/5


 


now we have to find out the point of intersection of these two planes.


let x=0


so  y-z =1   and   -3y + z =2


 so y=-3/2


   z = -5/2


 


so equation of line become


 (x-0)/2  = (y +3/2)/3  = (z+5/2)/5


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Badiuddin

7 years ago
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