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ANAM V. RANGA REDDY Grade: Upto college level
        

The vertices of a triangle are (0, 0),(sec θ, tanθ) and (4, -5) (0<θ<∏/2). The minimum possible area is --------

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear ANAM




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open determinant


Δ =1/2| [-5secΘ -4tanΘ]|


Δ =1/2| [5secΘ +4tanΘ]|


  clearly at Θ =0 both tanΘ  and sec Θ is minimum in there given domain.


so put Θ=0


Δ =5/2


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Badiuddin

7 years ago
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