Free JEE Adv 2013 solutions
1.] the equation of a locus is x2+y2-4x+6y-3=0.Show that the equation becomes x2+y2=16 if the origin is shifted.
(x-2)2 + (y+3)2 =16
this is a equation of circle having center ( 2,-3)
so now shift the origin at (2,-3)
so equation become x2+y2 =16
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