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```				   Q:- Two systems of rectangular axes have the same origin. If a plane cuts them at distances a,b,c and a1,b1,c1 from the origin, then
A.(1/a^2)+(1/b^2)+(1/c^2)=(1/a1^2)+(1/b1^2)+(1/c1^2)
B. (1/a^2)-(1/b^2)+(1/c^2)=(1/a1^2)-(1/b1^2)+(1/c1^2)
C. (a^2)+(b^2)+(c^2)=(a1^2)+(b1^2)+(c1^2)
D.(a^2)-(b^2)+(c^2)=(a1^2)-(b1^2)+(c1^2)
```

6 years ago

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```										Dear Tapasranjan
equation of planes are
x/a + y/b + z/c =1
and
x/a1  + y/b1 + z/c1 =1
since the axis is roatated but the origin and the plane is same so perpendicular distance from the origine to both the plave will be same
|1|/√{1/a2 + 1/b2 +1/c2}  = |1|/√{1/a12 + 1/b12 +1/c12}
or
√{1/a2 + 1/b2 +1/c2}  = √{1/a12 + 1/b12 +1/c12}

or
1/a2 + 1/b2 +1/c2  = 1/a12 + 1/b12 +1/c12

Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very  quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin

```
6 years ago

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