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Tapasranjan Das Grade: 12
        

Q:- Two systems of rectangular axes have the same origin. If a plane cuts them at distances a,b,c and a1,b1,c1 from the origin, then


A.(1/a^2)+(1/b^2)+(1/c^2)=(1/a1^2)+(1/b1^2)+(1/c1^2)


B. (1/a^2)-(1/b^2)+(1/c^2)=(1/a1^2)-(1/b1^2)+(1/c1^2)


C. (a^2)+(b^2)+(c^2)=(a1^2)+(b1^2)+(c1^2)


D.(a^2)-(b^2)+(c^2)=(a1^2)-(b1^2)+(c1^2)

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Tapasranjan


equation of planes are 


x/a + y/b + z/c =1


and


 x/a1  + y/b1 + z/c1 =1


since the axis is roatated but the origin and the plane is same so perpendicular distance from the origine to both the plave will be same


|1|/√{1/a2 + 1/b2 +1/c2}  = |1|/√{1/a12 + 1/b12 +1/c12}


or


 √{1/a2 + 1/b2 +1/c2}  = √{1/a12 + 1/b12 +1/c12}




or


1/a2 + 1/b2 +1/c2  = 1/a12 + 1/b12 +1/c12




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Badiuddin



7 years ago
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