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from a pointA (1,1),straight lines AL and AM are drawn at right angles to the pair of straight lines 3x2+7xy-2y2=0...then combined equation of AL and AM is............
Dear shivanshi
3x2+7xy-2y2=0
m1 + m2 = 7/2
m1.m2 =-3/2
now let a line a'(x-1)2 + 2h'(x-1)(y-1) + b'(y-1)2 =0 whose line is perpendicular to the these lines
m3 = -1/m1
m4 = -1/m2
m3 + m4 = -(m1+m2)/m1m2
-2h'/b' = 7/3
m3.m4 = -1/m1m1
a'/b' = -2/3
a'(x-1)2 + 2h'(x-1)(y-1) + b'(y-1)2 =0
or
a'/b' (x-1)2 + 2h'/b' (x-1)(y-1) + (y-1)2 =0
- 2/3 (x-1)2 -7/3 (x-1)(y-1) + (y-1)2 =0
2 (x-1)2 +7 (x-1)(y-1) +3 (y-1)2 =0
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