MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
shivanshi asthana Grade: 11
        

if the pairof the lines ax2+2axy+2bxy+by2=0 lie along the diameters of a circle and divide it into four sectors such that area of one of the sectors  is thrice that of the other then which of the following is true??


3a2-2ab+3b2=0


3a2-10ab+3b2=0


3a2+2ab+3b2=0


3a2+10ab+3b2=0

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear shivanshi


ax2+2axy+2bxy+by2=0 lie along the diameters of a circle


these two lines are diameter of circle,only possible if the center of circle is at origin.






6971-2191_7662_untitled.JPG


one part is 3 times the other then angel of onle part must be thrice the other


 so angel between two lines must be 45


tan45 = 2√(h2-ab)/(a+b)


1 = 2√((a+b)2-ab)/(a+b)


(a+b)2 = 4[((a+b)2-ab)]


3a2+2ab+3b2=0



Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 3,180 off
USE CODE: CART20
Get extra Rs. 297 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details