Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
shivanshi asthana Grade: 11
```        if the pairof the lines ax2+2axy+2bxy+by2=0 lie along the diameters of a circle and divide it into four sectors such that area of one of the sectors  is thrice that of the other then which of the following is true??
3a2-2ab+3b2=0
3a2-10ab+3b2=0
3a2+2ab+3b2=0
3a2+10ab+3b2=0```
7 years ago

147 Points
```										Dear shivanshi
ax2+2axy+2bxy+by2=0 lie along the diameters of a circle
these two lines are diameter of circle,only possible if the center of circle is at origin.

one part is 3 times the other then angel of onle part must be thrice the other
so angel between two lines must be 45
tan45 = 2√(h2-ab)/(a+b)
1 = 2√((a+b)2-ab)/(a+b)
(a+b)2 = 4[((a+b)2-ab)]
3a2+2ab+3b2=0
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Analytical Geometry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details