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sudarshan gupta Grade: Upto college level
`        A(4,4) and B(-4,4) are two points on the circle x^2+y^2=32 and P is any point on the circle.Prove that the angular bisector of angle APB pass through a fixed point. `
7 years ago

147 Points
```										Dear sudarshan

angular bisector of angel must made 45/2 angel with each line AP and BP
we know
tan 45 = 2tan45/2 /(1- tan245/2)
let tan 45/2  = m
so 1= 2m/(1-m2)
m2 +2m -1 =0 ................1

now slope of line AP (m1) = (4- 4√2sinθ)/((4-  4√2cosθ)
slope of bisector m2 = (y-  4√2sinθ)/((x-  4√2cosθ)

so tan45/2 =m= (m1-m2)/(1+m1m2)
put value of m1 and m2 and simplify
√2 cosθ ( -mx-4m +y -4) + √2sinθ (-my -4m+4-x) +(mx +my +32m -y +x) =0
solve coefficiet of cosθ and sinθ  and find value of x and y and put it in constant term if it satiesfied it then this line always pass throug this point for all value of θ.
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7 years ago
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