Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        sir pls solve ths quotion
if a circle of constant radius 3k passes through the origin and meets the axes at A and B the locus of the centeroid of the triangle ABC is.

```
7 years ago

147 Points
```										Dear rohan

let centroid of circle is (l,m)
then point A and B will be as shown in figure
and center of circle will be (3l/2 ,3m/2)

so  (3k)2 =(3l/2)2 +(3m/2)2
(2k)2 =(l)2 +(m)2
so locus
x2 +y2 =4k2

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin

```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details