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```				   ple solve this qutn
prove that the locus of center of the circle

1\2(x2+y2)+ x cosA + y sinA - 4 = 0
is x2+ y2 = 1

```

6 years ago

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```										Dear rohan
1\2(x2+y2)+ x cosA + y sinA - 4 =  0
or (x2+y2)+ 2x cosA + 2y sinA - 8 =  0
center of circle is (-cosA ,-sinA)
let center of circle is (h,k)
so h=-cosA   and k=-sinA
h2+k2 =sin2A +cos2A
h2+k2 =1
so locus
x2+y2 =1

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin
```
6 years ago

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