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```        ple solve this qutn
prove that the locus of center of the circle

1\2(x2+y2)+ x cosA + y sinA - 4 = 0
is x2+ y2 = 1

```
7 years ago

147 Points
```										Dear rohan
1\2(x2+y2)+ x cosA + y sinA - 4 =  0
or (x2+y2)+ 2x cosA + 2y sinA - 8 =  0
center of circle is (-cosA ,-sinA)
let center of circle is (h,k)
so h=-cosA   and k=-sinA
h2+k2 =sin2A +cos2A
h2+k2 =1
so locus
x2+y2 =1

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```
7 years ago
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