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find the sum of all the natural numbers between 1 and 200 which are neither divisible by 2 nor5
sum of odd terms from 1to 199
number of terms is =100 (tn=a +(n-1)d)a=1;d=2;tn=199
Sn(odd)=n/2[a+l]=50*200=10000
now deduct the term which are multiples of 5
a=5
d=10
tn=>195=5+(n-1)10
n=10
Sn=n/2[a+l]
5*200=1000
.:.total=10000-1000=9000
1+2+............+200=n/2(a+l)=200/2(1+200)=100(201)=20100-10100(div by 2)=10000, 10000-(5+15+......195)=10000-20/2(5+195)=10000-2000=8000
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