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```				   Let ABCD be a parallelogram whose diagonals equations are: AC:x+2y=3; BD: 2x+y=3. if length of diagonal AC=4 units and area of ABCD =8 units. Find the length of BD, AB and BC.
```

6 years ago

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```										Dear harshit
point of intersection of these two line are (1,1)
digonal cut each other at mid point
length of second digonal
area=1/2 *d1 *d2 *sinθ     where θ is angel between these two lines
8 =1/2 *4 *d2 *3/5
d2=20/3
BD=20/3
now you can find the point on line AC which is at d1/2=2 unit in both the direction of point (1,1)
these points will be A and C
similarly  you can find the point on line BD which is at d2/2=10/3 unit in both the direction of point (1,1)
these points will be Band D
once you know the point you can easly find the length of sides

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.  All the best.  Regards, Askiitians Experts Badiuddin
```
6 years ago

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