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`        Let ABCD be a parallelogram whose diagonals equations are: AC:x+2y=3; BD: 2x+y=3. if length of diagonal AC=4 units and area of ABCD =8 units. Find the length of BD, AB and BC.`
7 years ago

147 Points
```										Dear harshit
point of intersection of these two line are (1,1)
digonal cut each other at mid point
length of second digonal
area=1/2 *d1 *d2 *sinθ     where θ is angel between these two lines
8 =1/2 *4 *d2 *3/5
d2=20/3
BD=20/3
now you can find the point on line AC which is at d1/2=2 unit in both the direction of point (1,1)
these points will be A and C
similarly  you can find the point on line BD which is at d2/2=10/3 unit in both the direction of point (1,1)
these points will be Band D
once you know the point you can easly find the length of sides

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```
7 years ago
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