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				   in a triangle abc if the product of sines of the angles of a triangle is P and if the product of cosines of a triangle is Q then the equation whose roots are tanA,tanB,tanC is?

6 years ago


Answers : (1)


Dear sameer sai


sinA sinB sinC=p

cosA cosB cosC =q

so tanA tanB tanC =p/q

and A+B+C=180

use tan(a+b+c) formula

u will get  tanA+tanB+tanC=tanA tanB tanC

  so        tanA+tanB+tanC=p/q


tanAtanB +tanB tanC+ tanC tanA=(sinA sinB cosC +sinB sinC cosA +sinC sinA cosB)/cosA cosB cosC

                                               =1/q (sinA sinB cosC +sinC [sinB cosA + sinA cosB])

                                               =1/q (sinA sinB cosC +sinC [sin(A+B)])

                                               =1/q (sinA sinB cosC +sin2C )

                                               =1/q (sinA sinB cosC +1-cos2C )

                                               =1/q (1+cosC{-cosC+sinA sinB } )

                                               =1/q (1+cosC cosA cosB  )

                                               =1/q (1+q )

now  u can get equation.

            qx3 -px2 +(1+q)x -p =0



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6 years ago

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