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If (6,0),(0,6),(6,6) are the vertices of a triangle then distance between its circumcentre and centroid.
Dear pallavi bhardwaj
clearly the given triangle is a right angle triangle, right angle at (6,6)
centroid (4,4)
and circumcentre of a triangle lies on the mid point of hypt.
circumcentre {(6+0)/2,(0+6)/2} =(3,3)
now distance ={(4-3)2 +(4-3)2}1/2
=√2
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