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The length of the chord of the parabola y2=x which is bisected at the point (2,1) is?


a)51/2     b)4*31/2     c)3*31/2     d)2*51/2

4 years ago

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Answers : (1)

										

T = S1


y-0.5(x+2) = 1^2 - 2 = -1


 


2y - x - 2 = -2


or, x = 2y


 


Put in the equation,


 


y^2 = 2y


or, y = 0 , 2


x = 0, 4


Points where the line cuts the parabola = (0,0), (4,2)


 


Length = sqrt(4^2 + 2^2) = sqrt(16+4) = sqrt(20) = 2*sqrt(5)


 


Option (d)

4 years ago

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