if median of triangle are 5 cm 6cm and 7cm then find area of this triangle.


2 years ago

Share

                                        Ans:Let the median length be m1, m2& m3. Then area of triangle A is:$A = \frac{4}{3}\sqrt{S(S-m_{1})(S-m_{2})(S-m_{3})}$where S is$S= \frac{m_{1}+m_{2}+m_{3}}{2}$$S= \frac{5+6+7}{2} = 9$$A = \frac{4}{3}\sqrt{S(S-m_{1})(S-m_{2})(S-m_{3})}$$A = \frac{4}{3}\sqrt{9(9-5)(9-6)(9-7)}$$A = \frac{4}{3}\sqrt{9.4.3.2}$$A = 8\sqrt{6}$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

5 months ago

More Questions On Analytical Geometry

Post Question

Vouchers
To Win!!!
A ray of light coming from the point (1,2) is reflected at a point A on the x-axis and then passes through the point (5,3). What are the co-ordinates of point A?

Hello Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty

 Arun Kumar 5 months ago

Assume the x-axis to be a mirror. take the image of (1,2) in x-axis i.e(1,-2). as we know that reflected ray when extended back passes through the image of a point on incident ray i.e...

 siddharth gupta 5 months ago
A tangent to the ellipse x 2 +4y 2 =4 meets the ellipse x 2 +2y 2 =6 at P &Q.The angle b/w the tangents at P & Q of ellipse x 2 +2y 2 =6 is......

Draw the 2 ellipse in the figure. At a point(take for instance (0,1) for convenience and symmtry), draw a tangent to the first ellipse cutting the second at 2 points. As we know the slpoe of...

 Ravi 20 days ago
prove that the the perpediculars drawn from the vertices of a triangle on the sides facing them are concurrent.

Hello Student, Please find the proof of this: Let us draw (construct) the straight line GH passing through thepoint C parallel to the triangle side AB. Such a line does exist due to...

 Nishant Vora 2 months ago
Hello, I would like to ask you that do you only entertain Indians or also other nationalities? Thanks.

this forum is for all over the world student, most of our student are NRIs , so its for all of you.