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                   if median of triangle are 5 cm 6cm and 7cm then find area of this triangle.


3 years ago

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                                        Ans:Let the median length be m1, m2& m3. Then area of triangle A is:$A = \frac{4}{3}\sqrt{S(S-m_{1})(S-m_{2})(S-m_{3})}$where S is$S= \frac{m_{1}+m_{2}+m_{3}}{2}$$S= \frac{5+6+7}{2} = 9$$A = \frac{4}{3}\sqrt{S(S-m_{1})(S-m_{2})(S-m_{3})}$$A = \frac{4}{3}\sqrt{9(9-5)(9-6)(9-7)}$$A = \frac{4}{3}\sqrt{9.4.3.2}$$A = 8\sqrt{6}$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

one year ago

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show that √2+√2+√2=2cos8θ.

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 Vijay Mukati one month ago

My Pleasure.

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Find the last number of the following number series 10, 8, 16,13, 39, 35, ___ a.) 75 b.) 100 c.) 130 d.) 140 Explain

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 ng29 3 months ago

D because of 10-8=2 8*2=16 16-13=3 13*3=39 39-35=4 35*4=140

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