if median of triangle are 5cm,6cm,7cm then find the area
                   

2 years ago

Share

Answers : (1)

                    In case of medians
Remember the following formulae



Arun Kumar
IIT Delhi
Askiitians Faculty
2 months ago

Post Your Answer

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
two lines 5x-12 y=10 and 5x-12y=40 touches a circle C1 of diameter 6 if the centre of C1 lies in the first quadrant , find the equation of the circle C2 which is concentric with C1 and cuts...
 
 
in your question no circle with the given diameter can touch both the given lines Thanks and Regards, M.MURALIKRISHNA askIITians faculty
  img
MuraliKrishna Medavaram 5 months ago
 
Distance between 2 parallel lines (in this case the given lines) is given by : (c1-c2) / (a^2+b^2)^1/2 [where c1 and c2 are constants]. In this case the distance between the parallel lines...
 
Ansh Arora 5 months ago
Given a circle of equation x^2 + y^2 - 6x + 12y + 15 =0. find the equation of its mirror image with respect to the line y = 12x + 15
 
 
u can jst do tis by the formula (h-x1/a = k-y1/b =-2(ax1+by1+c)/root a^2+b^2
 
ratna teja honey one year ago
 
hi chase PFA for solution
 
jitender lakhanpal one year ago
If p(x) be a polynomial of degree 3 satisfying p(−1) = 10, p(1) = −6 and p(x) has maximum at x = −1 and p′(x) has minima at x = 1. Find the distance between the local maximum and local...
 
 
Hello Student, Let the polynomial be p(x)=ax^3 +bx^2 +cx+d p(-1)=–a + b – c + d = 10 p (1) = a + b + c + d = –6 p'(-1)=3a – 2b + c = 0 p''(1)= 6a + 2b = 0...
  img
Arun Kumar 15 days ago
if sin@+sin^2@=1 prove that cos^12@+3cos^10@+3cos^8@+cos^6@-1=0
 
 
sin@+sin^2@=1 =>sin@=1-sin^2@=cos^2@ Now cos^12@+3cos^10@+3cos^8@+cos^6@-1 Using cos^2@=sin@ in this expression we get sin^6@+cos^6@+3cos^10@+3cos^8@-1 =1-3sin^2@cos^2@+3cos^10@+3cos^8@-1...
  img
Rinkoo Gupta 3 months ago
 
given sin@=1-sin 2 @=cos 2 @ therefore sin 6 @+3sin 5 @+3sin 4 @+sin 3 @-1 ={sin 2 @+sin@} 2 -1=1-1=0 Thanks & Regards Sunil Raikwar askIITian's Faculty
  img
Sunil Raikwar 3 months ago
find sum 1^2*C1+3^2*C3+5^2*C5....
 
 
Hello Student, Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
  img
Arun Kumar 16 days ago
View all Questions »