let x2 +y2 -4x-2y-11=0 be a circle.a pair of tangents from the points (4,5) with a pair of radii form a quadrilateral of area...

2 years ago

Share

Answers : (2)

                                        

12

2 years ago
                                        

  • means its centre at2,1 and radii 4.it is at adis.from 2 so area of one triangle from quadilateral is 8.so another is also a right angled triangle  so its area 4. so total area 12


2 years ago

Post Your Answer

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
If in a triangle A=(1,10),circumcenter=(-1/3,2/3) and orthocentre =(11/3,4/3) then the co-ordinates of the side opposite to A is:
 
 
STEP 1:USE THE CONCEPT THAT CENTROID DIVIDES THE LINE SEGMENT JOINING ORTHOCENTRE. AND CIRCUMCENTRE IN THE RATIO 2:1 CALCULATE THE COORDINATES OF CENTROID(G) AS (1,8/9). STEP 2:CENTROID=((X...
 
siddharth gupta 2 months ago
No of normals can be drawn through a given point to the parabola,ellipse
 
 
In general there are three normals to a parabola and four to an ellipse through a given point.
 
India VK one year ago
 
infinite
 
naresh masaboina one year ago
From a point (sin k,cos k),three normal can be drawn to the parabola y^2=4ax(a>0) then then value of a lies in the interval: 1)(2,5/2) 2)(0,1/2) 3)(2,3) 4)(1/2,3/2)
 
 
Hi, The equation of the normal to the parabola y 2 = 4ax is y = mx – 2am – am 3 , where m is the slope of the tangent line corresponding to the normal. If the normal passes...
 
VENNA RAMANJANEYA REDDY one month ago
Find the real values of the parameter ‘a’ for which atleast one complex number z =x+iysatisfies both the equality | z- ai | = a+4 and the inequality | z-2 |
 
 
Hello Student, Please find the answer to your question below [|z-ai| = a + 4] [|z-2| < 1] For these two to have atleast one solution, then both circles must intersect [|x+iy-ai| = a+4]...
  img
SHAIK AASIF AHAMED one month ago
Find doamin of f(x) g(x)=|sinx|+sinx h(x)=sinx+cosx , x is in b/w 0 to pi f(x)=(logh(x) g(x))1/2 log is in square root answer is pi/6,pi/2 pls give two solution graph and analytical. thanks
 
 
Ans: 1st Part: 2nd Part: 1st Condition: …...........(1) 2nd Condition: …...............(2) Final Solution: Intersection of (1) & (2) Thanks & Regards Jitender Singh IIT...
  img
Jitender Singh 2 months ago
what is the periof of modulus of sin(x)cos(x)
 
 
Ans: Hello Student, Please find answer to your question below Period of f(x) = sin2x Since we are taking the modulus, then negatib=ve part of the graph will come on +ve side which is similar...
  img
Jitender Singh one month ago
 
period of sinx and cos x is 2pi modulus of sinx *cosx =2*sinxcosx/2 =2*modulus of sin2x period of sin2x=2pi/2=pi thus its period is pi
  img
Sunil Kumar FP one month ago
View all Questions »