MY CART (5)

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
                   

from the origin,chords are drawn to the circle square(x-1) +square(y)=1.the equation of the locus of the mid pt. of these chord is....

3 years ago

Share

Answers : (2)

                                        x^2+y^2=x
                                        
3 years ago
                                        

O(0,0) lies on the circle.


general form of any point on this circle is given by (-g+r(cosØ),-f+r(sinØ)) hence here it is P(1+1(cosØ),1(sinØ)).


thus for mid pt. of chord OP:


x= (0+1+1cosØ)/2 =>(1+cosØ)/2    (1)


y=sinØ/2;     (2)


from (1) and (2), (cosØ)^2= (2x-1)^2,   (3)


                          (sinØ)^2=(2y)^2;     (4)


adding (3) and (4)


     sqr(2x-1)+sqr(2y)=1,


 or x^2 +y^2-x=0 ,which is the required eq.


 

3 years ago

Post Your Answer

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?
 
 
y 2 = px y = sqrt(px) Since x & y are perfect square integers, sqrt(x) is an integer. Since p is a prime no., sqrt(p) is an irrational no. The point which satisfies the given condition is...
 
Y RAJYALAKSHMI 10 months ago
sir what is parallelopiped this is asked in the mathematics exercise of 8 th grade but it is nowhere to be found in the book
 
 
In geometry, a parallelepiped is a three-dimensional figure formed by six parallelograms (the term rhomboidis also sometimes used with this meaning). By analogy, it relates to a...
  img
Sourabh Singh 10 months ago
 
a parallelepiped is a three-dimensional figure formed by six parallelograms. The rectangular cuboid (six rectangular faces), cube (six square faces), and the rhombohedron (six rhombus faces)...
  img
Yash Baheti 10 months ago
Q . THE EQUATION ax 2 + 2bxy + by 2 =0 REPRESENTS A PAIR OF LINES. COMBINED EQUATION OF LINES THAT CAN BE OBTAINED BY REFLECTING THESE LINES ABOUT X-AXIS IS - bx 2 – 2bxy + ay 2 = 0 ax 2 +...
 
 
Let (X,Y) be a point in the req locus. Clearly (X,Y) is the image of the point (X,-Y) wrt y=0. According to the question, (X,-Y) lies on ax 2 +2bxy+by 2 =0 Therefore aX 2 - 2bXY +bY 2 = 0...
 
Himaja 7 months ago
 
thanks.......
 
Bharat Makkar 7 months ago
What is the value of 0 ∫ π/4 (cos 2x) 11/2 cosxdx ? (0 is lower limit and π/4 is upper limit)
 
 
|1/13*sin 2x^13/2| limit 0 to pie/4 1/13
 
Neha 5 months ago
 
|1/13*sin 2x^13/2| limit 0 to pie/4 1/13
 
Neha 5 months ago
 
|1/13*sin 2x^13/2| limit 0 to pie/4 1/13
 
Neha 5 months ago
Find the real values of the parameter ‘a’ for which atleast one complex number z =x+iysatisfies both the equality | z- ai | = a+4 and the inequality | z-2 |
 
 
Hello Student, Please find the answer to your question below [|z-ai| = a + 4] [|z-2| < 1] For these two to have atleast one solution, then both circles must intersect [|x+iy-ai| = a+4]...
  img
SHAIK AASIF AHAMED 11 months ago
 
Dear student, Can you please mention the complete inequality. Is it either |z-2|> 0, or |z-2|<0 or any other number. Once, you can provide that detail, we can colve it further. Regards...
  img
Sumit Majumdar 11 months ago
View all Questions »