MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
KAMAL RAWAT Grade: 12
        

from the origin,chords are drawn to the circle square(x-1) +square(y)=1.the equation of the locus of the mid pt. of these chord is....

5 years ago

Answers : (2)

Vaishal Shah
50 Points
										x^2+y^2=x
										
5 years ago
omi more
30 Points
										

O(0,0) lies on the circle.


general form of any point on this circle is given by (-g+r(cosØ),-f+r(sinØ)) hence here it is P(1+1(cosØ),1(sinØ)).


thus for mid pt. of chord OP:


x= (0+1+1cosØ)/2 =>(1+cosØ)/2    (1)


y=sinØ/2;     (2)


from (1) and (2), (cosØ)^2= (2x-1)^2,   (3)


                          (sinØ)^2=(2y)^2;     (4)


adding (3) and (4)


     sqr(2x-1)+sqr(2y)=1,


 or x^2 +y^2-x=0 ,which is the required eq.


 

5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details