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the locus of the center of the circle which cuts orthogonally the circle x2 +y2-20x +4=0 and which touches x=2 is

4 years ago

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Answers : (3)

										x2+y2+2gx+2fy+c=0

condition for orthogonal,
2*g*10=c+4
perpendicular fron center to x=2 is radius..
f2=22g
put g=-x and f=-y
hence,y2=-22x
4 years ago
										sorry,there was one mistake in above solution.

Ans. Is y^2=16x.
4 years ago
										

how?plz tell me..urgent plz..

4 years ago

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