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the locus of the center of the circle which cuts orthogonally the circle x2 +y2-20x +4=0 and which touches x=2 is

3 years ago

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Answers : (3)

                                        x2+y2+2gx+2fy+c=0

condition for orthogonal,
2*g*10=c+4
perpendicular fron center to x=2 is radius..
f2=22g
put g=-x and f=-y
hence,y2=-22x
3 years ago
                                        sorry,there was one mistake in above solution.

Ans. Is y^2=16x.
3 years ago
                                        

how?plz tell me..urgent plz..

3 years ago

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