.ex 4.7 q.2, the locus of the center of the circle which cuts orthogonally the circle x2 +y2-20x +4=0 and whic

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Title: .ex 4.7 q.2

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Posted On: Jan 25, 2012 09:00 AM

the locus of the center of the circle which cuts orthogonally the circle x2 +y2-20x +4=0 and which touches x=2 is

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KAMAL RAWAT
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Vaishal Shah

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Jan 25, 2012 12:30 PM

x2+y2+2gx+2fy+c=0 condition for orthogonal, 2*g*10=c+4 perpendicular fron center to x=2 is radius.. f2=22g put g=-x and f=-y hence,y2=-22x

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Vaishal Shah

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Feb 17, 2012 06:25 AM

sorry,there was one mistake in above solution. Ans. Is y^2=16x.
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KAMAL RAWAT

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Mar 28, 2012 05:27 PM

how?plz tell me..urgent plz..

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