the equation of the tangent to the circle x2 +y2 +4x -4y+4=0 which make equal intercept on the positive coordinate axes is:

2 years ago

Share

Answers : (1)

                                        if tangent is y=mx+c.

Equal intercept means m=-1
x+y=c
perpendicular from center of the circle on tangent is radius.
C=2 root 2
x+y=2 root 2
2 years ago

Post Your Answer

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Out of 8 doctors, 6 arespecialists and 2 are MBBS. 3 doctors are selected in random. Find prob of distribution of the of the number of specialist doctors ?
 
 
There are three possibilities to select 3 people : (1) 1 is a specialist, 2 are non-specialists (X=1). (2) 2 are specialists, 1 is non-specialist (X=2). (3) all 3 are specialists (X=3)....
  img
bharat bajaj 6 months ago
 
There are three possibilities to select 3 people : (1) 1 is a specialist, 2 are non-specialists (X=1). (2) 2 are specialists, 1 is non-specialist (X=2). (3) all 3 are specialists (X=3)....
  img
bharat bajaj 6 months ago
The equation of a straight line passing through the point (-5,4) and which cuts an intercept of root(2) units between the lines x+y+1=0 and x+y-1 is?
 
 
Hello Student. Please find the solutionx+y+1=0 and x+y-1 are two parallel lines and distance between them is mod|\frac{1-(-1)}{\sqrt{2}} |So distabce between them is 2/root2 = root2So our...
  img
Nishant Vora 22 days ago
If the orthocentre of a triangle is at (4,5) and the centroid is at (3,3), where is the circumcentre located? Answer is (2.5,2). Please explain.
 
 
so.. centroid is dividing Orhtocentre and circumcentre in 2:1 internally use section formula if the circumcentre is (x, y) for X-coordinate: 3 = (4*1 + 2* x)/ 3 ….....(1) 9 =(4*1 + 2*...
  img
Ajay Verma 3 months ago
If a+b=c, prove that cos^2 a+cos^2b+cos^2c =1+2cosacosbcosc
 
 
cos^2a +cos^2b+cos^2c= (1+cos2a)/2+(1+cos2b)/2+cos^2c =1+(1/2)*(2cos(a+b)cos(a-b) +cos^2c (since a+b+c = 0) =1 + cos(-c)cos(a-b)+cos^2c (since cos(-a) = cosa) =1+cos(c)cos(a-b)+cos^2c...
 
Y RAJYALAKSHMI 3 months ago
Find the real values of the parameter ‘a’ for which atleast one complex number z =x+iysatisfies both the equality | z- ai | = a+4 and the inequality | z-2 |
 
 
Hello Student, Please find the answer to your question below [|z-ai| = a + 4] [|z-2| < 1] For these two to have atleast one solution, then both circles must intersect [|x+iy-ai| = a+4]...
  img
SHAIK AASIF AHAMED 3 months ago
 
Dear student, Can you please mention the complete inequality. Is it either |z-2|> 0, or |z-2|<0 or any other number. Once, you can provide that detail, we can colve it further. Regards...
  img
Sumit Majumdar 3 months ago
The product (1 + tan1°) (1 + tan2°) (1 + tan3°) ………. (1 + tan 45°) equal to ?
 
 
tan45° = (tana + tanb)/(1 - tana tanb) ........... where a + b = 45 { compound angle formula } tana + tanb = (1 - tana tanb)tan45° tana + tanb = 1 - tana tanb (1 + tan 1°) (1 +...
  img
Sourabh Singh one month ago
 
We can start with : =(1+tan 0 o )(1 + tan1°) (1 + tan2°) (1 + tan3°) ………. (1 + tan 45°) {Since , tan 0 o = 0} Now , we know that tan(A + B) = [ tan(A) +...
  img
Sunil Kumar one month ago
View all Questions »