MY CART (5)

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price:

There are no items in this cart.
Continue Shopping
                   

the area of the triangle formed by the tangent at the pt. (a,b) to the circle x2 +y2 =r2and the coordinate axis


 

3 years ago

Share

Answers : (1)

                                        

Equation of tangent is 


 


ax+by-r^2 = 0


In x-y intercept form


 


x/(r^2/a) + y/(r^2/b) = 1


 


x-intercept = r^2/b


y-intercept = r^2/b


 


Area of triangle = 1/2*r^2/b*r^2/b = r4/(2ab)

3 years ago

Post Your Answer

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
If the vertices of triangles are placed at (0,0), (0,6), (6,0). The prove that the distance between the orthocentre and circumcentre is 3 root2.
 
 
Solution: As we know the.. orthocentre is the point of intersection of altitudes of the triangle... soo for right angle triangle.. orthocenter is the vertex itself on which right angle is...
  img
Ajay Verma 8 months ago
please see the image.......
 
 
The centre will be (h,0). So the eqn will be (x-h) 2 + y 2 =52 This passes through (2,3) So will satisfy the eqn. Put the coordinates to find the value of h.
  img
Ravi one month ago
​Q. IF a,b,c ARE IN A.P THEN THE IMAGE OF THE POINT OF INTERSECTION OF THE FAMILY OF LINES ax + by + c=0 IN THE LINE y=0 LIES ON THE LINE- x + 2y – 5 = 0 2x = y =0 3x + 4y + 5 =0 3x + 4y –...
 
 
Since a,b,c are in AP let a = A - d, b = A, c = A + d ax+by+c = A( x+ y+ 1) – d(x – 1) = 0 The point of intersection of the given family of lines is the point of intersection of the lines...
 
Himaja 3 months ago
 
Since a,b,c are in AP let a = A - d, b = A, c = A + d ax+by+c = A( x+ y+ 1) – d(x – 1) = 0 The point of intersection of the given family of lines is the point of intersection of the lines...
 
Himaja 3 months ago
 
Since a,b,c are in AP let a = A - d, b = A, c = A + d ax+by+c = A( x+ y+ 1) – d(x – 1) = 0 The point of intersection of the given family of lines is the point of intersection of the lines...
 
Himaja 3 months ago
If p,q are the roots of the quadratic equation x 2 -10rx-11s=0 and r,s are roots of x 2 -10px-11q=0,then find the value of p+q+r+s.
 
 
Hello student, Please find the answer to your question below Givenx 2 -10rx-11s=0........(1) x 2 -10px-11q=0....(2) As p is a root of 1 we get p 2 -10pr-11s=0 and r is a root of 2 so r 2...
  img
SHAIK AASIF AHAMED 6 months ago
 
p, q are the roots of the quadratic equation x 2 - 10rx – 11s = 0 . r, s are the roots of the quadratic equation x 2 – 10px – 11q = 0. The two equations are perfectly symmetric with roots...
 
Satyajit Samal 6 months ago
 
1210
 
PRAMAY 7 months ago
Please tell how they calculate it sir please see attachment please
 
 
attachement is not visible, please write the quesion on forum , otherwise not possible to help you.
  img
Sher Mohammad 8 months ago
 
=5 +n/1 + n(n-1) / 2! + ….....+ n!/n! next step I want to understand (1+1)^n + 4 = 2^n + 4
 
milind 8 months ago
If x+y+z=1 Then (1-3x^2-3y^2-3z^2+2x^3+2y^3+2z^3)=?
 
 
Hello Student, Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
  img
Arun Kumar 8 months ago
View all Questions »