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The points (0, 8/3), (1,3) and (82, 30) are vertices of
(a) isoceles triangle
(b) an acute angled triangle
(c) right angled triangle
(d) None of these
Explain pls.
Dear Aditi,
square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2 } = 10/9 =1.11 b^2 = { (82-1)^2 + (30 -3)^2 } = 7290 c^2 = { (82-0)^2 + (30 -8/3)^2 } =7471.11 it shows that , c^2 > a^2 + b^2 so the tiangle would be acute
square of one side ,a^2 = { (0-1)^2 + (8/3 -3)^2 } = 10/9 =1.11
b^2 = { (82-1)^2 + (30 -3)^2 } = 7290
c^2 = { (82-0)^2 + (30 -8/3)^2 } =7471.11
it shows that , c^2 > a^2 + b^2
so the tiangle would be acute
Best Of luck
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