MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Vbhootna Vb Grade: 11
        

Find the equation of the chord of the parabola y 2 = 12x which is bisected at the point (5, –7)

6 years ago

Answers : (1)

Pramod J AskiitiansExpert-IIT-B
36 Points
										

Dear student,


let (x1,y1) and (x2,y2) be two point be on parabola and (5,-7) is their midpoint


=> x1+x2 = 10 , y1+y2 = -14


yi^2 = 12xi


=> y1^2 + y2^2 = 120 and y1+y2 = -14


=> y1+y2)^2 = 196


=> 120 + 2y1y2 = 196


=> y1y2 = 38 => y2 = 38/y1


substitute it in y1+y2 = -14


=> y1^2 + 14y1 + 38 = 0


=> y1 = -3.68 , x1 = 1.13 and y2 = 10.316 , x2 = 8.869


line passing through (x1,y1) and (x2,y2) is y= (-6/7)x + (-19/7)

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 4,500 off
USE CODE: SSP3
Get extra R 280 off
USE CODE: MOB20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details