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```        the circle x^2+y^2-8x+4y+4=0 touches
a)x-axis
b)y-axis
c)both axes
d)neither
??
i evaluated by putting values of x and y as zero and got real values which states it touches both axes??dosent it?
but solution says b)y-axis  ```
6 years ago

510 Points
```										dear anmol
on putting x=0 , we have
y2+4y+4=0
(y+2)2 = 0
y=-2                only 1 value of y that means it touches y axis ...
now at y=0 , we have
x2-8x+4 = 0
here we have 2 reaL values of x , that means it cuts the x axis at two points ..
so option b is correct
```
6 years ago
Durgesh Prasher
21 Points
```										DO YOU KNOW THAT COORDS OF CENTRE OF CIRCLE ARE {-1/2 COEFF. OF X ,-1/2  COEFF. OF Y}
RADIUS OF CIRCLE [X1,Y1] IS UNDER ROOT OF X1^2 +Y1^2 -C
FOR THIS EQUATION COORDS ARE [4,-2]
SO IT WILL TOUCH Y AXIS AS ABSICCA =RADIUS
```
6 years ago
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