MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
anmol nanda Grade: 11
        the circle x^2+y^2-8x+4y+4=0 touches

a)x-axis
b)y-axis
c)both axes
d)neither
??
i evaluated by putting values of x and y as zero and got real values which states it touches both axes??dosent it?
but solution says b)y-axis
6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

dear anmol


on putting x=0 , we have


y2+4y+4=0


(y+2)2 = 0


y=-2                only 1 value of y that means it touches y axis ...


now at y=0 , we have


x2-8x+4 = 0


here we have 2 reaL values of x , that means it cuts the x axis at two points ..


so option b is correct

6 years ago
Durgesh Prasher
21 Points
										

DO YOU KNOW THAT COORDS OF CENTRE OF CIRCLE ARE {-1/2 COEFF. OF X ,-1/2  COEFF. OF Y}


RADIUS OF CIRCLE [X1,Y1] IS UNDER ROOT OF X1^2 +Y1^2 -C


FOR THIS EQUATION COORDS ARE [4,-2]


N RADIUS IS 4


SO IT WILL TOUCH Y AXIS AS ABSICCA =RADIUS

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 3,180 off
USE CODE: CART20
Get extra Rs. 297 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details