MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 280 off
USE CODE: MOB20

				   

If the co-ordinates of points P,Q & R satisfy the relation xy=c2, show that the orthocentre of the triangle PQR also satisfies this relation

6 years ago

Share

Answers : (1)

										

THERE IS ONE LONG METHOD AND SHORT METHOD ... 


 LONG METHOD: CONSIDER THREE POINTS OF P,Q,R AS (X1,Y1),(X2,Y2),(X3,Y3)  NOW SINCE ORTHOCENTER IS THE INTERSECTION OF ALTITUDES SO FIND THE EQUATION OF ALTITUDES . AND FIND THE INTERSECTING POINTS AND PUT THE POINTS IN THE EQUATION WHICH IS GIVEN AND SEE IF IT SATISFIES .... EQUATION OF THE ALTITUDE WILL BE FOUND OUT BY


 YOU WILL KNOW THE SLOPE OS THE SIDES SINCE YOU HAVE THE POINTS AND ANY LINE PERPENDICULAR TO IT WILL HAVE SLOPE EQUAL TO -1/THE SLOPE OF THE LINE   THEN YOU CAN FIND EQUATION BY POINT FORM AND PROCEED.......


 ..........................................................................................................................................................................


SHORT METHOD..... IF YOU LOOK AT THE EQUATION CAREFULLY YOU WILL (XY=C^2) NOTICE THAT THIS EQUATION IS THE LOCUS OF POINTS ON A RECTANGULAR HYPERBOLA  ......... SO THERE IS ONE PROPERTY THAT IF THREE SIDES OF THE TRIANGLE LIES ON A RECTANGULAR HYPERBOLA THEN THE ORTHOCENTER OF THE TRIANGLE WILL ALSO LIE ON THE RECTANGULAR HYPERBOLA

4 years ago

Post Your Answer

Other Related Questions on Analytical Geometry

The shortest distance between the line y-x=1 and curve x=y^2 is? Please give detailed answer and explanation Thanks
 
 
Mannon Mani, we cannot use that nethod because he took the points in both the curve and line with respect to t, which is incorrect as they are non intersecting. They cannot be taken with the...
 
2017 years ago
ABCD is a rectangle. P and Q are on AB and BC respectively such that the area of triangle APD =5, Area of triangle PBQ=4 and area of triangle QCD=3, area of triangle DPQ is
 
 
The answer is go fuck yourself. To make this more than 100 characters, I may add that you should masturbate in your own room.
 
Xyz 29 days ago
 
Your answer is 12. I will post full answer tommorow, I feel sleepy today by the way brilliant question.
 
Paras Verma 6 months ago
 
in this triangles the area of dpq is 6 because it is a triangle of inceasing order in such triangles they defer by onlyone so the area is 6
 
bharath 6 months ago
if the lines joining the origin to the intersection points of the y=mx+2 and the curve x^2+y^2=1 are at right angle , then Plus 2 and the Cursed squared plus y squared
 
 
There is a formula you can check it in any coordinate geometry book(such as s k goyal,etc) which gives the joint equation of the pair of lines joining the origin and point of intersection of...
 
Piyush Kumar Behera 2 months ago
 
If the lines joining the origin to the intersecting points of the y=mx+2 and the curve x 2 +y 2 =1 are at right angle, then (1) m 2 =1 (2) m 2 =3 (3) m 2 =7 (4) 2m 2 =1 now please give me...
 
Prabhav Sharma 2 months ago
 
Make the question clear.I cant get what the question is trying to ask.The last part of the question is not clear. please use the latex to make it clear.
 
Piyush Kumar Behera 2 months ago
If alpha is a real root of the equation ax 2 +bx+c and beta is a real root of equation -ax 2 +bx+c. Show that there exists a root gama of the equation (a/2)x 2 +bx+c which lies between alpha...
 
 
 
Ajay 6 months ago
 
Small Mistake in last para posting again..............................................................................................................
 
Ajay 6 months ago
 
We have Similarly, So if P(x) = a/2 x 2 +bx +c, then and are off opposite sign and hence there must exist a root between the two numbers.
 
mycroft holmes 6 months ago
In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??
 
 
The value of gamma is still not correct, either printing mistake or you gave me wrong value. The correct value of gamma is below
 
Ajay 5 months ago
 
Thankyou so much............................. …......................................................................!
 
Anshuman Mohanty 5 months ago
 
Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7
 
Anshuman Mohanty 5 months ago
if |z - i| Options: a*) 14 b) 2 c) 28 d) None of the above
 
 
If |z-i| = ?? PLs complete the question
  img
Nishant Vora one month ago
 
Got it! [z + 12 – 6 i ] can be rewritten as [ z – i + 12 – 5 i] => | z – i | and => |12 – 5 i | = sqrt ( 12^2 + 5^2) = 13......................(2) => | z + 12 – 6 i | => | z + 12 – 6 i |...
 
Divya one month ago
 
I tried posting the question several times, it kept cutting off the rest of the question. Here: If | z-1| Options: a*) 14 b) 2 c) 28 d) None of the above
 
Divya one month ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off
USE CODE: MOB20

Get extra R 280 off
USE CODE: MOB20

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details