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nikhil sahota Grade: 12
        what is the angle subtended at the focus by the normal chord at the point (b, b)on the parabola y^2=4a(x-a)
6 years ago

Answers : (1)

Pramod J AskiitiansExpert-IIT-B
36 Points
										
Dear student,


(b,b) is a point on y=x line


y^2 = 4a(x-a) meets y=x at


=> x^2 = 4a(x-a) => x-2a)^2 = 0

=> (2a,2a) is the point and the slope of normal at this point is -1 i.e y=-x+4a is the equation of chord


y=-4a+x meets parabola at 4a(x-a) = x^2 + 16a^2 - 8ax

=> normal chord meets parabola at (10a,-6a)


focus of parabola is (2a,0)


Angle subtended by chord on focus = 90 + |tan-1 (-6/8)| => 126.870
6 years ago
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