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ADNAN MUHAMMED

Grade 12,

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I know that the section formula can be derived by using the similarity of triangles concept. But can it also be be derived using the distance between two points concept, i.e., for line AB with point p dividing it in the ratio m : n; here A = (x1,y1), B = (x2,y2) and p = (x,y). (distance of AP) / (distance of PB) = m/n I tried doing it but got ended up getting a very scary looking expression. Any help in this regard will be really appreciated. -Neel.

I know that the section formula can be derived by using the similarity of triangles concept.


But can it also be be derived using the distance between two points concept, i.e., for line AB with point p dividing it in the ratio m : n; here A = (x1,y1), B = (x2,y2) and p = (x,y).


 


(distance of AP) / (distance of PB) = m/n


 


I tried doing it but got ended up getting a very scary looking expression.


Any help in this regard will be really appreciated.


-Neel.


 

Grade:12

2 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

You are on the right track and this is the way of solving section formula....

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

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sudeep mohanty
18 Points
12 years ago

section formula

 

if a company wants to insert a tower between two points in a way such that building of  darshanam vatika is 5 times nearer to tower than the building of gordhan park.

 

darshanam vatika(34km,28km);gordan park(83km,56km)

 

position of tower=[5*34+83]/6 , 5*28+56/6]

                       = [253/6,196/6]

                       = [42.16km,32.66km]

the distance between dv and gp is divided in such a way that the tower is five times as close to dv than gp.Thuscoordinates of dv is taken five times than coordinates of gp.

you can check this:

difference of tower from dv(x coordinate)=42.16-34=8.16

difference of tower from gp(x coordinate)=42.16-83=-40.84km 0r distance=40.84km

therefore;40.84/8.16=5

 

 

 

 

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