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i want the solution of q. 9
thanks```
6 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear student,
The equation of the tangent at P(x1, y1) (xx1/a²) + (yy1/b²) = (x1²/a²) + (y1²/b²)  And the other tangent at Q(x2, y2) (xx2/a²) + (yy2/b²) = 1  The point T(x0, y0) belongs to both of these tangents, so: (x0x1/a²) + (y0y1/b²) = 1  and: (x0x2/a²) + (y0y2/b²) = 1  The next step is to simply state that the equation of the chord of contact is: (xx0/a²) + (yy0/b²) = 1

Now use the distance formula from (0,0) ie origin....

All the best.
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Sagar Singh
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```
6 years ago
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