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i want the solution of q. 9 thanks

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i want the solution of q. 9


thanks

Grade:12

1 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

The equation of the tangent at P(x1, y1)
(xx1/a²) + (yy1/b²) = (x1²/a²) + (y1²/b²)

And the other tangent at Q(x2, y2)
(xx2/a²) + (yy2/b²) = 1

The point T(x0, y0) belongs to both of these tangents, so:
(x0x1/a²) + (y0y1/b²) = 1

and:
(x0x2/a²) + (y0y2/b²) = 1

The next step is to simply state that the equation of the chord of contact is:
(xx0/a²) + (yy0/b²) = 1

 

Now use the distance formula from (0,0) ie origin....

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

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Sagar Singh

B.Tech, IIT Delhi

sagarsingh24.iitd@gmail.com

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