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nikhil arora Grade: 12
        

1132_24875_IMG_0303.JPG


 


i want the solution of q. 9


thanks

6 years ago

Answers : (1)

SAGAR SINGH - IIT DELHI
879 Points
										

Dear student,


The equation of the tangent at P(x1, y1)
(xx1/a²) + (yy1/b²) = (x1²/a²) + (y1²/b²)

And the other tangent at Q(x2, y2)
(xx2/a²) + (yy2/b²) = 1

The point T(x0, y0) belongs to both of these tangents, so:
(x0x1/a²) + (y0y1/b²) = 1

and:
(x0x2/a²) + (y0y2/b²) = 1

The next step is to simply state that the equation of the chord of contact is:
(xx0/a²) + (yy0/b²) = 1


 


Now use the distance formula from (0,0) ie origin....










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Sagar Singh


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sagarsingh24.iitd@gmail.com









6 years ago
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