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tangents PA and PB are drawn to an ellipse x^2/16+y^9=1 from the point (o,5) find the area of triangle pab
X2/16+Y2/9=1 is the eq of ellipse
chord of contact = XX1/16+YY1/9=1
chord of contact = 5Y/9=1
Y = 9/5 ..............1
putting Y=9/5 in the eq of ellipse then
X = + or - 16/5
so
A=(16/5,9/5) ,B=(-16/5,9/5) ,P=(0,5)
this triangle isoceles triangle with base AB & height of (5-9/5)units
area = (base)(height)/2
AB(base) = 32/5 ,height = 16/5
area = 256/25 square units
actually i am no idea about this because till now i study only general EQ.of ellipse so please tell me a hint to solve this question
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