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Pooja singh Grade: 11
        

If the line segment joining the points P(x1,y1) and Q(x2,y2) subtends an qngle @ at origin O 


prove that OP.OQcos@ = x1x2 +y1y2

6 years ago

Answers : (4)

Fawz Naim
37 Points
										

1256_22392_scan0002.jpg

6 years ago
Devasish Bindani
45 Points
										

hey yar


op.oqcos@=>x1.x2cos0+x1.y1cos90+x2.y1cos90+x1.y2cos90+x2.y2cos90+y1.y2cos0


since (x1 and x2) and (y1 and y2)are in straight line


766_22795_g.JPG

6 years ago
Devasish Bindani
45 Points
										

hey yar


by resolution of vectors


op.oqcos@=>x1.x2cos0+x1.y1cos90+x2.y1cos90+x1.y2cos90+x2.y2cos90+y1.y2cos0


since (x1 and x2) and (y1 and y2)are in straight line


766_22795_g.JPG


therefore the answer becomes


OP.OQcos@=x1x2+y1y2


since cos0=1 and cos 90=0


thus prooved

6 years ago
satyajit nandy
20 Points
										

 As the line OP and OQ subtends an angle @, so we can use cosine law...........


    2.OP.OQ.cos@ =(X1^2+Y1^2)+(X2^2+Y2^2)- {(X1-X2)^2+(Y1-Y2)^}


                                          =2X1X2+2Y1Y2


   SO OP.OQ.COS@= X1X2 + Y1Y2

6 years ago
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