Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        number of ways of selecting two numbers from 1 to 12 such  that  their  sum  is divisible by 3.`
8 years ago

Pratham Ashish
17 Points
```										Dear Naveen
for a no to be divisible by 3 , possibilities are 3,6,9,15,18,21
if 2 no. are x and y , den
eqns are
x + y = 3 ,x + y = 6, x + y = 9, x + y = 12 , x + y = 15 , x + y = 18 , x + y = 21
for 1st eqn x,y wud be 1 & 2
for 2nd set is (2,4),(1,5)
for 3rd (1,8),(2,7),(3,6),(4,5)
for 4th (1,11),(2,10),(3,9),(4,8),(5,7),(6,6)
for 5th (12,3),(11,4),(9,6),(10,5),(8,7)
for 6th (12,6),(11,7),(10,8)
for 7th (10,11)
just count the possibility and dat is ur ans
```
8 years ago
Harpreet Kaur Oberoi
18 Points
```										12
```
8 years ago
saumendra aggarwal
8 Points
```										48
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details