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naveen kumar sehrawat Grade: 10
        number of ways of selecting two numbers from 1 to 12 such  that  their  sum  is divisible by 3.
7 years ago

Answers : (3)

Pratham Ashish
17 Points
										

Dear Naveen


for a no to be divisible by 3 , possibilities are 3,6,9,15,18,21


if 2 no. are x and y , den


eqns are


x + y = 3 ,x + y = 6, x + y = 9, x + y = 12 , x + y = 15 , x + y = 18 , x + y = 21


for 1st eqn x,y wud be 1 & 2


for 2nd set is (2,4),(1,5)


for 3rd (1,8),(2,7),(3,6),(4,5)


for 4th (1,11),(2,10),(3,9),(4,8),(5,7),(6,6)


for 5th (12,3),(11,4),(9,6),(10,5),(8,7)


for 6th (12,6),(11,7),(10,8)


for 7th (10,11)


just count the possibility and dat is ur ans

7 years ago
Harpreet Kaur Oberoi
18 Points
										

12

7 years ago
saumendra aggarwal
8 Points
										48
										
7 years ago
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