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A line 3x+4y-5=0 cus the curve 2x^2 + 3y^2=5 at P and Q. Find angle POQ where O is the origin.

6 years ago


Answers : (1)


Dear Karthik,


SUbstitute value of x from the line into the curve and find out y and then x. Now find the slope of PO and QO by relation - slope  = y2-y1/x2-x1

Now u have 2 slopes m1 and m2

Use the formula tanθ = mod. ( m1-m2/1+m1m2)


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Askiitians Expert

Anil Pannikar

IIT Bombay

6 years ago

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