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Rahul Ramesh Grade: 11
        

find the equation of a circle which passes through the origin and cuts off chords of length 4 and 6 on the positive x axis and y axis resp

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

let equation of circle be x^2 +y^2 +2gx+2fy+c.............eq1


 as circle passes through origen therefore c=0


 x intersept is given by 2(g^2-c)^1/2 =4


 y intersept is given by 2(f^2-c)^1/2 =6


  we get (g,f)=(+_2,+_3)


   now eq1 becomes


                              x^2 + y^2  +_4x  +_6y =0 is the required circle

6 years ago
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