Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        FInd the equation of circle drawn on the intercept on diameter between the axes made by the line 3x+4y=12`
7 years ago

22 Points
```										Hi Rahul,
The anwer is :
3x + 4y = 12 or x/4 + y/3 = 1
Thus x intercept of line 3x + 4y = 12 is a = 4
and y intercept of line 3x + 4y = 12 is b = 3
The Intercept length will be root(32 + 42) = 5
Hence Diameter of circle will be 5 , thus radius will be 5/2
Now , Mid-point of Intercept will be ( 4/2 , 3/2 ) or ( 2 , 1.5 )
Hence center point of circle is ( 2 , 1.5 ) and radius is 2.5
Thus eqn of circle will be ( x - 2 )2 + ( y - 1.5 )2  = (2.5)2
Puneet
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Analytical Geometry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details