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Rahul Ramesh Grade: 11
        

FInd the equation of circle drawn on the intercept on diameter between the axes made by the line 3x+4y=12

7 years ago

Answers : (1)

Puneet Mittal AskiitiansExpert-IITD
22 Points
										

Hi Rahul,


The anwer is :


3x + 4y = 12 or x/4 + y/3 = 1


Thus x intercept of line 3x + 4y = 12 is a = 4


and y intercept of line 3x + 4y = 12 is b = 3


The Intercept length will be root(32 + 42) = 5


Hence Diameter of circle will be 5 , thus radius will be 5/2


Now , Mid-point of Intercept will be ( 4/2 , 3/2 ) or ( 2 , 1.5 )


Hence center point of circle is ( 2 , 1.5 ) and radius is 2.5


Thus eqn of circle will be ( x - 2 )2 + ( y - 1.5 )2  = (2.5)2


Please feel free to ask as many questions you have.


Puneet

7 years ago
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