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`        find the equation of circle passing through the points (1,1),(2,1)and (3,2)`
7 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										DEAR RAHUL,
The standard form of a circle whose centre is (g,f) and radius r is: x² + y² -2gx -2gy + c = 0, where r² = g² + f² - c  First, 'plug in' the co-ords. of the first given point: (1)² + (1)² -2g(1) - 2f(1) + c = 0  1+ 1 -2g -2f + c =0 2-2g-2f+c=0  Repeat for the next 2 given points. You obtain 3 simultaneous linear equations for g,f,c.  Solve them and 'plug' the values for g, f and c back into the standard equation. Hence, the eq'n. of the circle is thus obtained. {Incidentally, so is the radius: √[g² + f² -c] }

We are all  IITians and here to help you in your IIT  JEE preparation.  All the best.

Sagar Singh
B.Tech IIT Delhi
sagarsingh24.iitd@gmail.com

```
7 years ago
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