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`        find the radius of a circle which is concentric with the circle xsq+ysq-2x+6y-3=0 and whose radius is double the radius of the circle xsq+ysq-6x-1=0`
7 years ago

36 Points
```										Dear Ramesh
As you are asking for the radius of a circle whose radius is double the radius of the circle xsq+ysq-6x-1=0.We shall first find the radius of the above circle.
It can be written as (x-3)^2+y^2-9-1=0
(x-3)^2+y^2=10
comparing the above equatio with (x-a)^2+(y-b)^2=r^2.
and the desired circle radius =2√(10)
centre of  xsq+ysq-2x+6y-3=0 is
(x-1)^2+(y-(-3))^2=13
centre is (1,-3)
Seems you are asking for the circle equation with centre (1,-3) and radius 2√(10) is (x-1)^2+(y+3)^2=40.

thanks

```
7 years ago
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