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consider the points A=(0,1) and B=(2,0).let P be a point on the line 4x+3y+9=0.find the coordinate of P such that |PA-PB| is maximum
Hi Rahul,
You can calculate the coordinate of P by following the below approach :
let P be (h,k)
PA = root(h2 + (k - 1)2)
PB = root((h - 2)2 + k2)
let S = |PA-PB| = root(h2 + (k - 1)2) - root((h - 2)2 + k2) ---- eqn (1)
Since P lies on given line therefore , 4h + 3k + 9 = 0
Put k from this eqn into eqn(1)
and differentiate S w.r.t to h
S will be maximum when dS/dh = 0 and d2S/dh2 < 0.
Thus u will get vaule of h.
Please feel free to ask as mnay questions you have.
Puneet
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