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`        Find the equation of the bisector of the angle between   4x+y-7=0 and  x-4y+3=0 which contains the origin.`
7 years ago

A S
36 Points
```										Dear Aditya,
Suppose we have two equations ax++by+c=0 and px+qy+r=0. First we make c and r positive. Then equations of bisectors are-

For bisector containing origin, + sign is used and - sign for the other.
For your question, this method could be used.
Post all your doubts here. Kindly approve the answer if you like it.
Best of Luck!
Regards,
A S
```
7 years ago
Nehal Wani
21 Points
```
The Bisector Of These Lines Passes Through The Point Of Intersection Of These Lines As Well As Origin.
4x+y-7=0
or
16+4y-28.......................(i)
x-4y+3=0........................(ii)
Solving (i) and (ii)
We get:
x=25/17 and y=19/17
The Required Line Passes Through (0,0) and (25/17,19/17)
Therefore Equation:
19y-25x=0

```
7 years ago
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