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let the roots be a and b.
now subtracting 2 from each root ..
a-2 &b-2 r equal to reciprocal of original roots i.e a&b .
so,a-2=1/a &b-2=1/2
solving we get a=& b=1±√2
so we take a=1+√2 & b=1-√2
so
b^2+c^2+bc=(a+b)2 +ab2 +(a+b)*ab=4+1-2=3
hence the answer is 3
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