Solve the equation X^4-5*X^3+11*X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.

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The factors of the biquadratic equation are (x-1)(x-2)(x^2-2x+3).so by this relation we get value of a=1 & b=2

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Solve the equation X^4-5X^3+11X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.

Solve the equation X^4-5X^3+11X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.

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Solve the equation X^4-5*X^3+11*X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.

Solve the equation X^4-5*X^3+11*X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.

1 Answers

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Solve the equation X^4-5X^3+11X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.

Solve the equation X^4-5X^3+11X^2-13*X+6=0, given that two of its roots a and b are connected by the relation 3a + 2b=7.