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Question is from permutation and combination.please see the attachment.2 questions are provided.

Question is from permutation and combination.please see the attachment.2 questions are provided.

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Grade:11

1 Answers

Arun
25750 Points
6 years ago
For the first one,
 
Let the number of candidates = n
Now
nC1 + nC2 + nC3+ ......+ nC(n-1) = 2^n  -2 = 254
2^n = 256
n = 8 ways
 
Regards
Arun(askIITians forum expert)

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