Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????

Question

Vikas TU · Answer

Magnitude = root(3 + 1) = 2 and the argument that is thetha = arctan(1/root3) = 30 degree + 180 degree = 210 degree = 7pie/3 Hence the polar coordinates would be: => (2,7π/6)

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Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????

Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????

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Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????

Polar coordinate of point (-√3,-1) is (2,7π/6)Explain?????

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