if x2+px+q=0 and x2+p’x+q’=0 have one root in common, prove that its value is (q-q’)/(p’-p) or (pq’-p’q)/(q-q’)

Question

Vikas TU · Answer

Dear Student,

Let common root be m

subtracting the two equations we ge that x = (q - q’)/(p’ - p)

Multiply eq 1 with q' and eq 2 with q

Subtract 2 from 1 to get

M= (p'q-pq') / (q'- q).

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

Charu · Answer

If two equation x^2+px+q=0 and other one is x^+p'x+q'=0 then the common root is b1c2-b2c1/c1a2 -c2a1 =pq'-p'/q-q' Best of luck Charuanurag sharma

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if x2+px+q=0 and x2+p’x+q’=0 have one root in common, prove that its value is (q-q’)/(p’-p) or (pq’-p’q)/(q-q’)

if x2+px+q=0 and x2+p’x+q’=0 have one root in common, prove that its value is (q-q’)/(p’-p) or (pq’-p’q)/(q-q’)

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if x2+px+q=0 and x2+p’x+q’=0 have one root in common, prove that its value is (q-q’)/(p’-p) or (pq’-p’q)/(q-q’)

if x2+px+q=0 and x2+p’x+q’=0 have one root in common, prove that its value is (q-q’)/(p’-p) or (pq’-p’q)/(q-q’)

2 Answers

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