If omega(w) is a non real cube root of unity and n is not a multiple of 3,then..refer to the image Q.13

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pothamsetty chethan · Answer

by expanding thedeterminant , we get 1(1-w^3n)-w^n(w^2n-w^2n)+w^2n(w^4n-w^n) we know that w^3n=0and w^4n=w^n by using this both relations ,we get determinant =0 by u

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If omega(w) is a non real cube root of unity and n is not a multiple of 3,then..refer to the image Q.13

If omega(w) is a non real cube root of unity and n is not a multiple of 3,then..refer to the image Q.13

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If omega(w) is a non real cube root of unity and n is not a multiple of 3,then..refer to the image Q.13

If omega(w) is a non real cube root of unity and n is not a multiple of 3,then..refer to the image Q.13

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