if a+b+c=0, then the roots of the equation 4ax^2+3bx+2c=0, where a,b,c are real numbers are

Question

Vikas TU · Answer

Dear Student,
Given that:a+b+c = 0
a^2/(a^2 – bc) + b^2/(b^2 – ca) + c^2/(c^2 – ba).............(1)

Substituting in the eqn. (1)

a = -b-c or a^2 = (b+c)^2
we get,
2(a^2 +b^2 + ab)/(a^2 +b^2 + ab)

=> 2

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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if a+b+c=0, then the roots of the equation 4ax^2+3bx+2c=0, where a,b,c are real numbers are

if a+b+c=0, then the roots of the equation 4ax^2+3bx+2c=0, where a,b,c are real numbers are

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if a+b+c=0, then the roots of the equation 4ax^2+3bx+2c=0, where a,b,c are real numbers are

if a+b+c=0, then the roots of the equation 4ax^2+3bx+2c=0, where a,b,c are real numbers are

1 Answers

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