A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

Question

Vijay Mukati · Answer

Dear Student,

The locus will be the straight line satisfying x + y = root(2). Now to find the area you must be given other conditions also. as here we are not any closed curve to find its area.
Hence please verify your question again.

Thanks, Vj

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A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

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A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

A point moves in x-y plane such that the sum of its distances from two mutually perpendicular lines is always equal to 2^(1/2) units. The area encloced by the locus of the point is (in sq. units)

1 Answers

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Other Related Questions on Algebra

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